Thursday, December 27, 2012

Tiket Legoland

Siap sedia untuk ke legoland

2 Tiket Adult dan 2 Tiket Child -  RM 200 


bila lagi nak pegi kan?

Tuesday, December 4, 2012

CSC438 - DATA STRUCTURE - LAB BINARY TREE






package LAB_9_TREE; 

  class BinaryTreeNode {
    
    int data;
    BinaryTreeNode right;   
    BinaryTreeNode left;
    
    
    BinaryTreeNode(int a)
    {
        this.data = a;
    } 
  
}

 public class BinaryTree {
    
    protected BinaryTreeNode root;
    
    // DEFAULT CONSTRUCTOR
    public BinaryTree()
    { 
        root = null; 
    }
    
    // DESTROY THE BINARY TREE
     public void destroyTree ()
    {
         root = null;
    }
    
    //DETERMINE WHETER THE BINARY TREE IS EMPTY
    public boolean isEmpty()
    {
        return ( root == null );          
    }
    // DETERMINE THE HEIGHT OF THE BINARY TREE
    public int treeHeight()
    {         
        return height(root);
    }    
    
    // A RECURSIVE FUNCTION TO GET THE HEIGHT OF THE BINARY TREE
    public int height( BinaryTreeNode p )
    {
        if ( p == null )
            return 0;
        else
            return 1 + max(height(p.left),height(p.right) );
        
    }
    
    // COMPARE THE TWO VALUE FROM THE LEFT AND THE RIGHT NODE
    public int max( int x,int y)
    {
        if ( x >= y )
            return x;
        else
            return y;
        
    }
    
    
    
    //INSERT A NEW NODE INTO THE BINARY TREE
    public void insertNode(int item)
    {
        BinaryTreeNode current;
        BinaryTreeNode trailCurrent = null;
        BinaryTreeNode newNode;
        
        newNode = new BinaryTreeNode(0);
        
        newNode.data = item;
        newNode.left = null;
        newNode.right = null;
        
        if(root == null)
            root = newNode;
        else
        {
            current = root;
            while(current != null)
            {
                trailCurrent = current;
                if(current.data == item)
                {
                    System.err.print("The insert item is already in the list. Duplicate item are not allowed");
                    return;
                    
                }
                else
                    if(current.data < item)
                        current = current.left;
                    else
                        current = current.right;
                       
            }
             
            if(trailCurrent.data < item)
                trailCurrent.left = newNode;
            else
                trailCurrent.right = newNode; 
            
        }
        
    }
      
}

============================================================



package LAB_9_TREE; 

import javax.swing.*;

public class TestBinaryTree 
{

    public static void main(String[] args)
    {
        BinaryTree tree = new BinaryTree(); 
        int value;
        System.out.println("Inserting the following values : ");
        
        for ( int i = 0; i < 10 ; i++)
        {
            value = (int) (Math.random()*100);
            System.out.print(value + " "); 
            tree.insertNode(value);
        } 
    } 
}

/*
  
 The output :
 
 Inserting the following values : 
 45 60 63 72 67 20 1 28 99 30
 
  
  
 */


prefix and postfix the easy ways

Find the prefix and postfix notation for the following infix expression:

(a + b – c) * (e / f) – ( g – h/i)
There is a quick way to convert from one notation to another. You start by inserting all the implicit brackets/parentheses that determine the order of evaluation, regardless of what notation the expression is already in. So, taking the expression above and adding these implicit brackets gives:
This is before:
(a + b - c) * (e / f) - ( g - h/i)

This is after adding the implicit parentheses:
( ( ( (a + b) - c) * (e / f)) - ( g - (h/i)))
Now, in order to convert from one notation to another using the bracketed form, you would move the operator in each bracketed expression. Where you move the operator depends on the notation that you want to convert to.

Postfix vs. Prefix Notation

If you want to convert to postfix notation, you would move the operator to the end of the bracketed expression, right before the closing brace. To convert to prefix notation, you would move the operator to the beginning of the bracketed expression, right after the opening brace. So, (h/i) in postfix notation would look like (h i /), and in prefix notation would look like (/ h i ). Do this for every operator in a bracket. So, converting the expression above to prefix notation will give you:
Moving all the operators to the beginning of the 
bracketed expression for prefix notation gives us:
( - ( *  (  - ( + a b) c)  ( / e f))  ( - g ( / h i ) ) )
And finally, removing all the parentheses gives us our final prefix notation:
- * - + a b c / e f - g / h i
Try figuring out how to get the postfix notation on your own using the rules given above. You should get this as your answer:
a b + c - e f / * g h i / - -

i got (((ab)+c)-(ef/)*)(g(hi/)-)-)


Thursday, October 18, 2012

Hari Raya Aidiladha dan Qurban.


Sempena Hari Raya Qurban 2012 kami sekeluarga sepakat untuk membuat qurban 2 bhg lembu sempena hari yang mulia ini.
Dizaman yang maju ini, mudah aje skrg nak buat qurban. bayar online sahaja dan buat akad untuk dilaksanakan qurban di kawasan yang amat memerlukan bantuan lebih lebih lagi saudara seislam di luar negara disana.

Harga Untuk satu bhg lembu hanyalah RM230 dan qurban hanya boleh dibuat pada Hari Raya Aidiladha dan Hari Tasyrik iaitu 11, 12 dan 13 Zulhijjah dengan tujuan untuk beribadah atau menghampirkan diri kepada Allah SWT.

sama samalah kita membudgetkan diri sekali setahun untuk perkara yang sangat sangat dituntut bagi umat islam.

untuk tempahan boleh lah ke laman web eQurban.com disini





FAQ

Soalan 1 :
Apakah yang dimaksudkan dengan Korban?
Korban bermaksud hampir. Dari segi istilah bermaksud menyembelih binatang tertentu pada Hari Raya Aidiladha dan Hari Tasyrik iaitu 11, 12 dan 13 Zulhijjah dengan tujuan untuk beribadah atau menghampirkan diri kepada Allah SWT.

Soalan 2 :
Apakah hukum melaksanakan ibadah korban?
Hukum korban ialah Sunat Muakkad (ibadah sunat yang sangat-sangat dituntut ke atas umat Islam yang berkemampuan. Namun begitu ia dihukumkan wajib apabila seseorang itu bernazar.

Soalan 3 :
Apakah binatang yang disyariatkan untuk korban?
Binatang yang hendak dikorbankan mestilah mempunyai ciri-ciri tidak cacat, tidak sakit, tidak buta, tidak berkurap dan tidak kurus. Binatang yang sah untuk dikorbankan adalah seperti berikut :
  1. Kambing biri-biri – berusia satu tahun dan ke atas.
  2. Kambing biasa -  berusia dua tahun dan ke atas.
  3. Unta – berusia lima tahun dan ke atas.
  4. Lembu atau kerbau – berusia dua tahun dan ke atas.

Soalan 4 :
Berapakah bilangan minimum haiwan yang digalakkan untuk ibadah korban?
Bagi haiwan seperti lembu, kerbau atau untuk bilangan minimum untuk ibadah korban adalah 1 bahagian. Manakala kambing bilangan minimum adalah satu ekor.

Soalan 5 :
Saya telah melaksanakan ibadah korban sebelum ini, bolehkah saya melaksanakannya lagi?
Boleh, ibadah korban boleh dilaksanakan seberapa banyak sekiranya berkemampuan.

Soalan 6 :
Jika saya menyertai program ibadah korban ini dengan pihak eQurban, apakah bukti yang menunjukkan ibadah korban tersebut telah dilaksanakan.
Pihak eQurban akan mengeluarkan sijil aku janji sebagai wakil melaksanakan ibadah korban tersebut kepada semua peserta dan menghantar gambar-gambar berkaitan yang menunjukkan ibadah tersebut telah dilaksanakan.

Soalan 7 :
Apakah kelebihan menyertai ibadah korban dengan pihak eQurban?
Kami menternak sendiri lembu-lembu untuk Korban ini di ladang kami di Stungstreng, Kemboja dengan usahasama Koperasi Muslim Kemboja. Bekalan lembu ini cukup untuk bekalan Qurban dan Aqiqah sepanjag tahun




Tuesday, August 28, 2012

Thursday, August 16, 2012

coldfusion tutorial



for those who want to learn coldfusion... alot of site is available for your reference...

 i found that this 2 site is very useful and got a lot of stuff you can learn as a beginner or intermediate level cf programmer...



Friday, August 3, 2012

Coldfusion Hosting

I Love Coldfusion.
It is simple, easy and user friendly.
i mean whut more you want if you want to develop a web base application.

check this out, a promotion from http://www.efree2net.com/free-domain-hosting.cfm

it's comes with a 20 GB space and bla bla as usual features.

and it also give you a free domain name just for US 25.

now i have my own coldfusion 9 hosting. 


Result Exam Sem 20122

Syukur Alhamdulillah, result aku untuk semester ini kira cemerlang jugak la.. dpt AD keseluruhannya.
kiranya taktik aku dengan mengambil kursus yang senang senang aje pada semester ini berbaloi la rasanya. harap harap semester depan dpt macam nie kan bagus, tapi yang penting usaha, dan teknik belajar. smart study la kata org jerman.


Thursday, August 2, 2012

Monday, July 23, 2012

Batman VS ‘The Joker’ dalam The Dark Knight Rises



Aku dah tgk dan crita batman yang baru tu... kira kira memang best jugak la, takde la kartun sgt macam masa zaman val kilmer dan george clooney tu. ada la realitinya kalau nak jadi superhero ikut masa sekarang nie.



Sempena tayangan filem Batman-The Dark Knight Rises yang baru nie, satu kejadian tembakan telah berlaku di sebuat panggung wayang di Denver ( bukan di gotham sebab kat sana ada batman original ). ikut ceritanya, banyak jugak penonton yang pakai costume Batman, tapi tidak sempat buat apa apa, sebab "The Joker" telah bertindak lebih pantas.

banyak motif tembakan ini dilakukan, dan mengikut sumber yang tidak boleh dipercayai adalah disebabkan tiada lagi character "the joker" dalam The Dark Knight Rises dan ini mengakibatkan kebosanan tahap gaban peminat dengan villain villain yang dipaparkan dalam filem yang baru ini.

nasib la ini adalah final installment dari trilogi batman ini, jika tidak anda perlu pakai baju kalis peluru untuk menonton wayang nanti, hanya di US, bukan di Gotham City.



‘The Joker’ tiru aksi penyerang Norway


credit to berita harian



James Holmes ikut manifesto serangan Anders Behring Breivik 

AURORA: Pembunuh 12 penonton di sebuah panggung wayang Denver dan menggelar dirinya ‘The Joker’ dilaporkan mengikut nasihat penyerang Norway, Anders Behring Breivik, apabila melakukan serangan ketika tayangan filem Batman: The Dark Knight Rises di sini, Jumaat lalu. James Holmes mengikut manifesto Breivik menyarankan penggunaan raifal, senapang patah, bom asap, senapang AR15 yang mampu melepaskan 100 kali tembakan, senapang Remington dan dua pistol Glock. 
Holmes juga mengikut apa yang disuruh Breivik dengan memakai pelindung leher, badan dan topeng gas mengikut manifesto 1,500 muka surat itu. 

Malah, Holmes, 24, menjadi ahli sebuah laman web dewasa mengikut cadangan Breivik supaya kerap melakukan hubungan seks sebelum serangan. 

Pasang bom di rumah 


Baca Seterusnya disini...

Peringatan Mesra - Potensi lebih 'boroi'


Nampaknya proses pemboroian telah bermula dengan adanya promosi dan diskaun untuk buffet ramadhan yang menyelerakan. aku pun macam dah tergoda nie dan dah berkira nak pi buffet mana la tahun nie... paling kurang at least sekali la kan, bukan selalu pun. 


hajat di hati nak dpt pinggang saiz 33 or 32 masa syawal nanti, akibat ketidak serasian seluar dengan saiz 35++ yang amat ketara. apa nak buat potensi boroi ini di sumbangkan oleh McD dan KFc dan nasi kukus kak nora seksyen 7 tu laaa... dah la sedap, boleh dpt hari hari plak tu...

ingatan untuk semua, jauhi boroi untuk hidup bahagia, katakan tidak pada makan berlebihan.


credit to utusan malaysia

Potensi lebih 'boroi'


Antara hidangan disajikan bertemakan Bazar Ramadan di sebuah hotel.

KUALA LUMPUR 22 Julai - Bagi sesetengah individu, kedatangan Ramadan dianggap sebagai peluang terbaik untuk menguruskan badan, sesuai dengan sifat amalan tersebut yang memerlukan umat Islam menahan lapar dan dahaga di siang hari.
Namun jangan terkejut sekiranya impian itu gagal dicapai sebaliknya perut anda kian 'menonjol' ketika syawal menjelma ekoran kegagalan menahan nafsu sewaktu berbuka puasa.
Menurut Pakar Pemakanan Hospital Pakar Ampang Pantai Puteri, Rose Hanizan Mat Hassan perkara itu tidak mustahil berlaku kerana pengambilan makanan secara berlebihan dan mengejut ketika perut kosong menyebabkan anggota badan itu cepat mengembang.
"Secara tidak langsung, ia menyebabkan perut seseorang ittu menjadi buncit. Justeru, umat Islam tidak sepatutnya makan seolah-olah 'melepas geram' ketika berbuka puasa," katanya.

Sunday, July 22, 2012

Friday, July 20, 2012

Panggilan Hangit - Baju Raya Oren



Dalam banyak banyak panggilan hangit HOT FM, yang ini paling aku tak boleh dengar, boleh sampai kluar air mata aku gelak bila dengar...


so korang enjoy la... untuk menghilangkan stress.








Wednesday, July 11, 2012

CSC435 - PAST EXAM QUESTION AND ANSWER


this is the past year question and the answer. have fun!




QUESTION 5  (APRIL 2008)

Given the following program segment:

public class Land
{    protected String owner;
     protected double area;

     abstract double calcTax();
     abstract void display();
     public Land( String own, double area)
           {
            //method definition
           }
}

public class Housing extends Land
{
     private char houseType;
     private double tax_rate;

     public Housing(String own,double area,char Hsetype)
     {
         //method definition
     }
     public double calcTax()
     {
        //method definition
     }
     public void display()
     {
        //method definition
     }
}

public class Agriculture extends Land
{
     private double fixed_tax_rate = 3.00;

     public Agriculture(String own,double area)
     {
        //method definition
     }
          public double calcTax()
     {
        //method definition
     }
     public void display()
     {
        //method definition
     }     }

a)         Define the method calcTax()of class Housing based on the following:

The tax for this type of land depends on its area and the type of house built on the land:

House Type
Description
Tax Rate (RM/m2)
T
Terrace
10
S
Semi-Detached
15
B
Bungalow
20
C
Condominium
5
                       
                                                                                                  (4 marks)
b)       Define method calcTax()of class Agriculture. Agricultural lands are all charged a fixed rate of RM 3 per meter square (m2).
                                            (2 marks)
                                   
b)            Write an application program that uses the concept of polymorphism to

i.          store data on various types of land. The number of data to be stored and information on each land are given by the user. The input process stops when the users key-in a sentinel value.

            ii.          Display the total Tax for all lands.
           
iii.         Display the Tax amount for Housing lands only.

iv.      Determine and display the highest tax for Agriculture land.
                                                                                                                        (12 marks)

APRIL 2008

a)    Answer:
       
        public double calcTax()
        {
       double tax=0.0;          ->0.5 mark
        if (houseType == 'T')
       { 
             tax_rate = 5;
             tax = area * tax_rate;
        }                        ->0.5 mark
       else if (houseType == 'S')
       {
            tax_rate = 10;
            tax = area * tax_rate;
        }                        -> 0.5 mark
        else if (houseType == 'B')
        {
             tax_rate = 15;
             tax = area * tax_rate;
        }                        ->0.5 mark
        else if (houseType == 'C')
        {
             tax_rate = 20;
             tax = area * tax_rate;
       }                          -> 0.5 mark
             return tax;          -> 0.5 mark
   }note : 1 mark if program correct

b)    Answer:
   private double fixed_tax_rate = 3.00; ->0.5 mark
   public double calcTax()
  {
       double tax = fixed_tax_rate * area;  -> 1 mark
       return tax;       -> 0.5 mark   }
                         
c)    Answer:
      public class TestLand
      {
        static Scanner console = new Scanner(System.in);
        public static void main(String[] args)
        {
           String owner,type;
           double area;
           char hsetype;
           double taxRate;
           char input = 'Y';
           int count =0;
       
           Land[] L = new Land[20];
           while(input != 'N')
           {
               System.out.print("Enter the land owner : ");
               owner = console.next();
               System.out.print("\nEnter the land area : ");
               area = console.nextDouble();
               System.out.print("Enter the land type: H-Housing,A- 
                                   Agriculture ");
               type = console.next();
           
               switch(type.charAt(0))
               {
                case 'H' :   System.out.println("Enter house type : ");
                             hsetype = console.next().charAt(0);
                             //taxRate = console.nextDouble();
                             L[count] = new Housing(owner,area,hsetype);
                             break;
                case 'A' :   L[count] = new Agriculture(owner,area);
                             break;
                default  : System.out.println( "Wrong land type");
            }
            count++;
            System.out.println("Do you want to continue ?(Y or N) : ");
            
            input = console.next().charAt(0);
        }
        System.out.println("length ="+L.length);
        for(int k=0; k<count;k++)
        {
            L[k].Display();
        }
        System.out.println("Count ="+count);
        double totalTax=0.0;
        for(int k=0; k<count;k++)
        {
           
            totalTax = totalTax + L[k].calcTax();
        }
        System.out.println("Total tax = "+totalTax);
        for (int k=0; k < count; k++)                   
         {   
           
            if (L[k] instanceof Housing) 
            {
               System.out.print("Tax amount for Housing land = ");
                 System.out.println(L[k].calcTax());    
              }
          }
        
double highest = 0.0;
         for (int k=0; k < count; k++)                  
         {   
            if (L[k] instanceof Agriculture)
                 if (L[k].calcTax() > highest)
                        highest = L[k].calcTax();
         }
         System.out.println("Highest tax for agriculture land = "+highest);

    }
QUESTION 3 (APRIL 2009)

Given the following inheritance hierarchy
 






And the definition for the BankAccount class:

abstract class BankAccount
{
     private String name;
     private long accNum;
     private double balance;   

   public BankAccount() {}

   public BankAccount(String name, long accNum, double balance)
   { //method definition}

     public String getName()
{  //method definition  }

public long getAcc()
{  //method definition  }

public double getBalance()
{  //method definition  }

public String toString()
{  //method definition  }

//method to update the balance for the account
public abstract double updateBalance();
}

a)    Define the Saving class that inherits from the BankAccount class. The attributes and methods are as follows:

Attributes: interest rate

Methods:
·         Constructor with arguments
·         toString(), to return the string representation of the object
·         updateBalance(), given the formulae:
update = (interest rate X balance) + balance;
 (10 marks)

b)    Define the Current class that inherits from the BankAccount class. The attributes and methods are as follows:

Attributes: interest rate and transaction fee
Methods:
·         Constructor with arguments
·         toString(), to return the string representation of the object
·         updateBalance(), given the formulae:
update = (interest rate X balance) + balance – transaction fee;
 (10 marks)

c)    Write a Java application class called BankApp that uses the concept of polymorphism to perform the following tasks:
·         Declare an array of objects to store data on various types of BankAccount.
·         Display the details for all bank customers.
·         Display the details of customer whose balance exceeding RM 100,000
·         Calculate and display the total balance of all Saving accounts and total balance of all Current accounts.
 .(15 marks)

APRIL 2009               
a)     
public class Saving extends BankAccount
{
    private double rate;

    public Saving(String name, long accNum, double balance,
double rate)
    {
        super(name, accNum, balance);
        this.rate = rate;
    }

   public String toString()
   {   
return super.toString() + " Interest rate: " + rate;
    }

    public double updateBalance()
    {
        double update = (rate * super.getBalance()) +
                             super.getBalance();
        return update;
    }
}

b)  public class Current extends BankAccount
{
   
    private double rate;
    private double fee;
   
    public Current(String name, long accNum, double balance,
double rate, double fee)
    {
        super(name, accNum, balance);
        this.rate = rate;
        this.fee = fee;
    }

    public String toString()
    {    return super.toString() + " Interest rate: " + rate + " Fee:"
 + fee;   
     }

    public double updateBalance()
    {
        double update = (rate * super.getBalance()) +
 super.getBalance() - fee;
        return update;
    }
}

c)  import javax.swing.*;

public class BankApp
{
    public static void main(String args[])
    {
      int n = Integer.parseInt(JOptionPane.showInputDialog(" Number
                of customers: "));
       
       BankAccount[] acct = new BankAccount[n];
       
      for(int i = 0; i < acct.length; i++)
      {
         String nm = JOptionPane.showInputDialog("Customer's Name: ");
         long accNo = Long.parseLong(JOptionPane.showInputDialog
(" Account #: "));
         double bal = Double.parseDouble(JOptionPane.showInputDialog
(" Balance: "));
           
       String type = JOptionPane.showInputDialog("Type - (S)aving/"
 + "(C)hecking ");
        char accType = type.toUpperCase().charAt(0);
            
     if (accType == 'S')
    {
     double rt = Double.parseDouble(JOptionPane.showInputDialog
(" Interest rate: "));
       acct[i] = new Saving(nm, accNo, bal, rt);
     }
     if (accType == 'C')
     {
         double irate =  Double.parseDouble
  (JOptionPane.showInputDialog (" Interest rate: "));
         double tfee = Double.parseDouble(JOptionPane.showInputDialog                  
                        (" Transaction fee: "));
         acct[i] = new Current(nm, accNo, bal, irate, tfee);
     }
   }
   for (int i = 0; i < acct.length; i++)
   {
        System.out.println(" The details of customers : " +
                     acct[i].toString());
           
        if (acct[i].updateBalance() > 100000)
            System.out.println(" The customers with balance > 100000:"
                            + acct[i].toString());
    }
     double saveBalance = 0, currBalance = 0;
     for(int i = 0; i < acct.length; i++)
     {
            if(acct[i] instanceof Saving)
                saveBalance += acct[i].updateBalance();
            if(acct[i] instanceof Current)
                currBalance += acct[i].updateBalance();
     }
     System.out.println(" Total Balance for Saving account: " +
                     saveBalance);
     System.out.println(" Total Balance for Current account: " +
                     currBalance);
    }
}
QUESTION 3 (NOV 2009)

Given the following definition

public abstract class Student
{
     private String name;
     private double test1;
     private double test2;
     private double test3;
     protected char grade;

      public Student(String n, double tl, double t2, double t3)
     { . . . }
     public abstract char computeGrade();

// Accessors
     public String getName() {...}
     public double getTest1() {...}
     public double getTest2() {...}
     public double getTest3() {...}
     public char getGrade (){...}
     public String toString (){...}
}

Suppose Undergraduate and Graduate extends Students, with no additional attributes. Using polymorphism, write a Java application to

a.    get the number of students and necessary data from the user. Store these data into an array of students
(10 mark)


b.    calculate and display the total number of students who get grade A and count how many of these students from each subclass, Undergraduate and Graduate.
(6 mark)


c.    Find and display the information of student whose name is given by the user
(4 mark)

QUESTION 3 (Nov 2009)

import javax.swing.*;
public class StudentApp
{
   public static void main(String args[])
  {
      int n = Integer.parseInt(JOptionPane.showInputDialog
(" Number of Students: "));
      Student[] stu = new Student[n];
      int under = grad = 0; 
      for(int i = 0; i < acct.length; i++)
      {
       String nm = JOptionPane.showInputDialog("Student's Name: ");
       double t1 = Double.parseDouble(JOptionPane.showInputDialog
(" Test 1: "));
       double t2 = Double.parseDouble(JOptionPane.showInputDialog
(" Test 2: "));
       double t3 = Double.parseDouble(JOptionPane.showInputDialog
(" Test 3: "));
          
      String type = JOptionPane.showInputDialog
("Type - (U)ndergraduate/" + "(G)raduate ");
       char stuType = type.toUpperCase().charAt(0);
       

if (stuType == 'U')
       {
          stu[i] = new Undergraduate(nm, t1, t2, t3);
       }
       if (stuType == 'G')
       {
          stu[i] = new Undergraduate(nm, t1, t2, t3);
       }  }
     for (int i = 0; i < stu.length; i++)
     {
         if( stu[i].getGrade() == ‘A’)
          {   
                if(stu[i] instanceof Undergraduate)
                     under++;
                if(stu[i] instanceof Graduate)
                           grad++;
      }    }
    System.out.println(" Total A student from Undergraduate: " +
 under);
    System.out.println(" Total A student from Graduate: " + grad);
    String input = JOptionPane.showInputDialog
("Search Student's Name: ");
    for (int i = 0; i < stu.length; i++)
    {
     if(input.equalsIgnoreCase(stu[i].getName())
           System.out.println(“Found “ + stu[i].toString());
    } } }
QUESTION 4 (NOV 2009)

Given the following inheritance hierarchy
 






and the list of data members and methods for ThemePark, WaterPark, and WildlifePark classes:

Superclass : abstract class ThemePark

Data member(s):
      String name;    // customer's name
     String icNo;    // customer's identification card number
     boolean member; // either member or not member of the park

Methods:
      ThemePark();
ThemePark(String name, String icNo, boolean member);
String getName();    // return the customer's name
String getlc();      // return the ic number
boolean getMember(); // return the membership
String toString();   // return the details of objects
abstract double calCharges(); // calculate the charges

Subclass : class WaterPark

Data member(s):
     boolean surfBeach; // either true or false to surf
     boolean waterRides; // either true or false to ride

Methods:
boolean getSurf();// return the surfing status
boolean getRide();// return the riding status
double calCharges();// calculate the charges
String toString();// return the details of objects

Subclass : class WildlifePark

Data member(s):
String category; // category of the customers

Methods:
String getCategory();// return the category
double calCharges();// calculate the charges



a)      Write the normal constructors for superclass and both subclasses.
 (6 marks)

b)      Given the details of ticket charges in table 5.1 and table 5.2 for both Water and Wildlife Parks below:

Activity
Cost(RM)
Surf Beach
25.00
Water Rides
20.00
Table 5.1 Details of ticket charges for Water Park

Category
Cost(RM)
Adult
35.00
Child
20.00
Table 5.2 Details of ticket charges for Wildlife Park


Write abstract methods named calcharges() to calculate the charges of the activities for both WaterPark and WildlifePark classes. The customers who are the members of the theme park will be given a special discount of 25% for every total charges.

(9 marks)

QUESTION 4 (Nov 2009)

a)         public ThemePark(String name, String ic, boolean member)
{
           this.name = name;
           this.icNo = ic;
           this.member = member;
}
public WaterPark(String name, String ic, boolean member, boolean surf,
 boolean ride)
{
     super(name, ic, member);
     this.surfBeach = surf;
     this.waterRides = ride;
}
public WildlifePark(String name, String ic, boolean member,
 String category)
{
super(name, ic, member);
     this.category = category;
}


b)         public double calCharges() // waterpark
{
          double total = 0;
          if( getSurf() == true)
                total = total + 25;
          if(getRide == true)
                total = total + 20;
    
          if(getMember() == true)
                total = total – (total * 0.25);

          return total;
}

public double calCharges() // wildlifepark
{
          double total = 0;
          if( getCategory().equalsIgnoreCase(“Adult”))
                total = total + 35;
          else if(getCategory().equalsIgnoreCase(“Child”))
                total = total + 20.00;
    
          if(getMember() == true)
                total = total – (total * 0.25);

          return total;
}

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